Softmax Regression

@goldpiggy,
I can’t understand too. :sweat_smile:

Hi @Gavin, great question. A simple answer is:

For more details, please check 22.7. Maximum Likelihood — Dive into Deep Learning 1.0.3 documentation

@goldpiggy
The simple answer seems to be Tautology.

I have read URL you give.
But I think it didn’t solve this question.
I can’t find anything in it.

@goldpiggy Many thanks! Finally understood it!

Really? @Gavin
image
What is it related to image ?
Could you explain it?

It’s explained in 3.4.8 :wink: @StevenJokes

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@goldpiggy.
ok…
just log image to

Hello. I am still not able to understand clearly how these 2 equations are related. Can you please explain, how for a particular observation i, the probability y given x is related to the entropy definition overall classes?


The green thing is same.

Thank you for your response. My question was more specifically why
image is same as
l(y,y_hat)

Is this because y when 1-hot encoded has only single position with 1 and hence when we sum up the y * log(y_hat) over the entire class, we are left with the probability y_hat corresponding to true y. Please advise.

@Abinash_Sahu
l (y,y _ hat)

Cross entropy loss
Only one type of these losses we often use.
https://ml-cheatsheet.readthedocs.io/en/latest/loss_functions.html


Q1.2. Compute the variance of the distribution given by softmax(𝐨)softmax(o) and show that it matches the second derivative computed above.

Can someone point me in the right direction? I tried to use Var[𝑋]=𝐸[(𝑋−𝐸[𝑋])^2]=𝐸[𝑋^2]−𝐸[𝑋]^2 to find the variance but I ended up having the term 1/q^2… it doesn’t look like the second derivative from Q1.1.

Thanks!

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It appears that there is a reference that remained unresolved:
:eqref: eq_l_cross_entropy

in 3.4.5.3

Thanks. Now it’s fixed. See comments in https://github.com/d2l-ai/d2l-en/issues/1448

to keep unified form,should the yj in later two equations should have an upper right mark (i) ?

me too. is there sth wrong?

I cannot understand the equation in 3.4.9

@Abinash_Sahu, @StevenJokess

I may have an explanation considering equivalence between log likehood and cross-entropy.

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Looks like you have der(E[X]^2), but what about E[X^2]? Recall:
Var[X] = E[X^2] - E[X]^2

From steps 2->3 and 3->4, does Sum_k_to_q actually resolve to q?

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