Single Variable Calculus

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How did the 3rd line in equation 18.3.10 get derived from the previous line?

Hi @ss007k, it is from (18.3.6). To be more specific, if you replace the x in (18.3.6) with β„Ž(π‘₯) , and replace πœ– in (18.3.6) with image, you will get the third line of (18.3.10).

Thank you; it’s definitely partially clear. What is still not so clear is how g(epsilon*dh/dx) caused [ dg/dh h(x) ] component to appear.

Hi @ss007k! That is derived by the chain rule!

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